An Optocoupler, is an electronic components that interconnects two separate electrical circuits by means of a light sensitive optical interface. We know from our . 3. Signal transmission between circuits of different po- tentials and impedances. □ Applications. DIP 4pin General Purpose. Photocoupler. 1. 4pin DIP package. The purpose of an optocoupler is to transfer signals from one circuit to another yet keep them galvanically isolated. Here I want . Thanks for clearity on ic
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Kannan E on July 19, at 9: The purpose of an optocoupler is to transfer signals from one circuit to another yet keep them galvanically isolated.
If the input is at 2V DC, then the output resistance should be around — ohms. First of all thanks for sharing such an useful information. Evis on November 12, at 7: Mihai on August 27, at Thank you for the information. I was wondering if i could just 817g the optcoupler and see if it works.
If the LED is good then we should check the phototransistor, you could measure it with the ohmmeter just like the LED between pins 3 and 4 the emitter and collectorand you should get a high resistance value both ways if the phototransistor is good. In my example an ohmmeter iptocoupler connected at the output, in order to see the change in resistance.
B Datasheet catalog
I have two circuits. Mihai on February 2, at 5: Mihai on March 6, at 2: I was referring to the junction resistance. Siroos on October 14, at I guess, it should work mostly the same as a normal triac.
Wade on February 5, at 9: Your email address oprocoupler not be published.
If i give the input of V DC what will be the response of this optocoupler…. Hi, Both methods are correct.
Sunil on March 3, at 3: It depends on the 2nd circuit you are supplying the voltage on collector of the optocoupler, optocoupler will never transfer the voltages of circuit1 to circuit2, it decreases resistance between your supplied voltages at collector and emitter on optockupler input of circuit2. This site uses Akismet to reduce spam.
The optocoupler is FL C F, should i just join the emittor and collector pins? For the triac pins 4 and 6with no voltage applied to the LED pins 1, 2check with an ohmmeter the resistance between pins 4 and 6, it should be high open circuit or at least greater than 1 megohm both ways, and this resistance should go down lower than ohms when voltage is applied to the LED, and should remain low even if the voltage is no longer present on the LED.
Some features may not work properly. Mihai on July 19, at 3: An optocouplerr or optoisolatoris a device that contains a light-emitting diode LED and a photosensor photodetector, such as a photoresistor, a photodiode, a phototransistor, …etc.
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measuring a optocoupler
Blumen on October 26, at 7: I appriciate… I tried that emprical method for H11B1 optocoupler. Mihai on July 16, at 5: The question is which optocouplr is the right testing method? Michael on January 21, at 3: Viliam on September 7, at 1: When Firefox stops working, you fire up Chrome. Shahid on August 7, at 1: Hi, maybe a stupid optocouller Muhammad Akhlaq on May 30, at 9: Did you reffer to isolation resistance when you mention some phototransistors have high resistance?
So when current flows through the LED, the triac is triggered and it conducts both ways until the main current drops below a certain optocouplsr.
In the datasheet example, a 10V DC is connected at the output, so that one can check the variation in voltage with a voltmeter or an oscilloscope.
Thx and best regards, Geert. If you get a value either way or no value at all, then certainly there is a problem with the LED, and you should find another optocoupler. Sarfaraz on November 8, at 9: The LED is basically a diode, and it should not conduct both ways not get values on the meter both ways.
Good design is as little 8177b as possible.